SOLUTION: Translate the sentence below and write the 2 equations. Then solve the equations using substitution or addition.
Six bananas and three kiwis cost $3.36. Two bananas and five kiwis
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Question 232281: Translate the sentence below and write the 2 equations. Then solve the equations using substitution or addition.
Six bananas and three kiwis cost $3.36. Two bananas and five kiwis cost $3.04. Find the cost of a banana and the cost of a kiwi.
b=
k=
Found 2 solutions by stanbon, unlockmath:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Translate the sentence below and write the 2 equations. Then solve the equations using substitution or addition.
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Six bananas and three kiwis cost $3.36. Two bananas and five kiwis cost $3.04. Find the cost of a banana and the cost of a kiwi.
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Equations:
6b + 3k = 336 cents
2b + 5k = 304 cents
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Multiply 2nd equation by 3 to get:
6b + 15k = 912
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Subtract that eq. from the 1st and solve for "k":
-12k = -576
k = 48 cents (price of a kiwi)
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Substitute that value into 2b + 5k = 304 to solve for "b":
2b + 5*48 = 304
2b = 64
b = 32 cents (price of a banana)
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Cheers,
Stan H.
Answer by unlockmath(1688) (Show Source): You can put this solution on YOUR website!
Hello,
Set up the following.
6 times b would give the cost of the bananas where b is the price of one banana.
3 times k would be the cost for the kiwis. Total is $3.36 The equation is:
6b + 3k = $3.36
The other equation would look like this:
2b + 5k = $3.04 Let's multiply this equation by -3 so to get 2b into -6b then we'll add both equations together.
6b + 3k = $3.36
-6b -15k = -9.12
We add the two above equations to get:
-12k = -5.76 Solve for k by dividing -12 into both sides.
k = .48 So the kiwi costs $0.48 each. Plug this into one of the original equations to look like this:
6b + 3(.48) = $3.36 Subtract $1.44 from both sides.
6b = $1.92 Divide each side by 6
b = $.32 So the bananas each cost $0.32
Kiwis cost $0.48 each
Bananas cost $0.32 each
RJ Toftness
www.math-unlock.com
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