SOLUTION: Find 3 consecutive odd integers such that twice the 2nd decreased by the 3rd is 3 less than twice the 1st

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 Question 231186: Find 3 consecutive odd integers such that twice the 2nd decreased by the 3rd is 3 less than twice the 1stFound 2 solutions by user_dude2008, stanbon:Answer by user_dude2008(1861)   (Show Source): You can put this solution on YOUR website!2(x+2)-(x+4)=2x-3 2x+4-x-4=2x-3 x=2x-3 x-2x=-3 -x=-3 x=3 <-------------- First # x+2=5 <-------------- Second # x+4=7 <-------------- Third # Answer by stanbon(57347)   (Show Source): You can put this solution on YOUR website!Find 3 consecutive odd integers such that twice the 2nd decreased by the 3rd is 3 less than twice the 1st ------------- 1st: 2x-1 2nd: 2x+1 3rd: 2x+3 ------------------------- Equation 2(2x+1) - (2x+3) = 2(2x-1)-3 4x+2-2x-3 = 4x-2-3 2x-1 = 4x-5 2x=4 x = 2 ---------- 1st: 2x-1 = 3 2nd: 5 3rd: 7 ------------------ Cheers, Stan H.