SOLUTION: find three consecutive odd integers such that the largest decreased by 3times the second is 47 less than the smallest.

Question 230378: find three consecutive odd integers such that the largest decreased by 3times the second is 47 less than the smallest.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find three consecutive odd integers such that the largest decreased by 3times the second is 47 less than the smallest.
---------------------------
1st: 2x-1
2nd: 2x+1
3rd: 2x+3
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Equation:
2x+3-3(2x+1) = 2x-1-47
2x+3-6x-3 = 2x-48
-6x = -48
x = 8
---------------
1st:2*8-1 = 15
2nd: 17
3rd: 19
=================
Cheers,
Stan H.
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