SOLUTION: one number is seven times a second number. four times the smaller number plus twice the larger number equals 36. find the number

Question 229420: one number is seven times a second number. four times the smaller number plus twice the larger number equals 36. find the number
Found 2 solutions by checkley77, MathTherapy:
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
x=7y
4x+2y=36
4*7y+2y=36
28y+2y=36
30y=36
y=36/30
y=6/5 ans.
x=7*6/5=42/5 ans.
Proof:
4*42/5+2*6/5=36
168/5+12/5=36
180/5=36
36=36

Answer by MathTherapy(10555) (Show Source): You can put this solution on YOUR website!
one number is seven times a second number. four times the smaller number plus twice the larger number equals 36. find the number

Let the smaller number be S, and the larger number L

Since the larger is 7 times the smaller, then L = 7S

And, since 4 times the smaller number, plus twice the larger number = 36, then:
4S + 2L = 36

Therefore, we have: L = 7S -----------(i)
....................................4S + 2L = 36 ------ (ii)

Subbstituting 7S for L in eq (ii), we get: 4S + 2(7S) = 36

4S + 14S = 36

18S = 36

S =

Since S, or the smaller number = , then the larger number, or L = ---- (7 * 2)
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