SOLUTION: The length and width of a square are increased by 6 feet and 8 feet respectively the result is a rectangle whose area is 188 square feet more than the area of the square. find the
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Question 229323: The length and width of a square are increased by 6 feet and 8 feet respectively the result is a rectangle whose area is 188 square feet more than the area of the square. find the length of the side of the square
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Let 
represent the measure of one side of the square. Then the area of the square is 
, the measure of one side of the rectangle is 
, the measure of the other side of the rectangle is 
, and the area of the rectangle is (x+8) = x^2 + 14x + 48)
, but the area of the rectangle is 
larger than the square, so:
Solve for .
John
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