SOLUTION: The sum of three numbers is 123. The second number is 9 less than two times the first number. The third number is 6 more than three times the first number. Find the three number

Question 228836: The sum of three numbers is 123. The second number is 9 less than two times the first number. The third number is 6 more than three times the first number. Find the three numbers. Thank you very much.
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
The sum of three numbers is 123. The second number is 9 less than two times the first number. The third number is 6 more than three times the first number. Find the three numbers. Thank you very much.

Step 1. Let n be the first number.

Step 2. Let 2n-9 be the second number since it is 9 less than two times the first number.

Step 3. Let 3n+6 be the third number since it is 6 more than three times the first number.

Step 4. Then n+2n-9+3n+6=123 since their sum is 123.

Step 5. Solving n+2n-9+3n+6=123 yields the following steps

Add 3 to both sides of the equation

Divide by 6 to both sides of equation

and .

Note the above numbers should add up to 123: 21+33+69=123...which it does.

Step 6. ANSWER: The numbers are 21,33, and 69.

I hope the above steps were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

Good luck in your studies!

Respectfully,
Dr J

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