SOLUTION: One number is three more than a second number. The sum of their squares is 37 more than the product of the numbers. Find the numbers.

Question 228601: One number is three more than a second number. The sum of their squares is 37 more than the product of the numbers. Find the numbers.
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
Let x = second number
x+3 = first number

Sum of squares IS 37 more than the product of the numbers.
x^2 + (x+3)^2= x(x+3) + 37
x^2 + x^2 + 6x +9 = x^2 +3x + 37

Set equation equal to zero by subtracting x^2 +3x + 37 from each side:
2x^2 + 6x + 9-x^2 -3x-37=0
x^2 + 3x - 28=0

This just happens to factor!
(x+7)(x-4)=0

There are two solutions:

First solution:
x=-7
x+3= -4

Second solution:
x=4
x+3= 7

Both solutions do check if you take the time to do it.

Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus

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