SOLUTION: find two consecutive odd integers such that the difference of their squares is 160.

Question 228596: find two consecutive odd integers such that the difference of their squares is 160.
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
Let x= first odd integer
x+2 = second odd integer

(x+2)^2 - x^2 = 160
x^2 + 4x + 4 - x^2 = 160
4x+4 = 160
4x=156
x= 39
x+2= 41

Check:
41^2- 39^2
1681-1521
=160 It checks!!

Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus

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