# SOLUTION: The sum of four consecutive odd integers is 216 . Find the four integers

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Question 226268: The sum of four consecutive odd integers is 216 . Find the four integers
Answer by drj(1380)   (Show Source):
You can put this solution on YOUR website!
The sum of four consecutive odd integers is 216 . Find the four integers

Step 1. Let n be the first odd integer.

Step 2. Let n+2, n+4, and n+6 be the next three consecutive odd integers

Step 3. Then, n+n+2+n+4+n+6=216 since the sum of the four consecutive odd integers is 216.

Step 4. Solving the equation in Step 4 yields the following steps

Solved by pluggable solver: EXPLAIN simplification of an expression

 Here's what you tried: This is an equation! Solutions: n=51. Graphical form: Equation was fully solved.Text form: n+n+2+n+4+n+6=216 simplifies to 0=0Cartoon (animation) form: For tutors: `simplify_cartoon( n+n+2+n+4+n+6=216 )` If you have a website, here's a link to this solution.

### DETAILED EXPLANATION

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Solved linear equation equivalent to 4*n-204 =0
It becomes .
Result:
This is an equation! Solutions: n=51.

### Universal Simplifier and Solver

Done!

With n=51, then n+2=53, n+4=55, and n+6=57. Also 51+53+55+57=216 as a check...

Step 5. The four consecutive odd integers are 51, 53, 55, and 57

I hope the above steps were helpful.

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And good luck in your studies!

Respectfully,
Dr J

drjctu@gmail.com

http://www.FreedomUniversity.TV