SOLUTION: I need to find two consecutive even intergers that sum 66.It would also help if i knew the formula to solving this.

Question 225091: I need to find two consecutive even intergers that sum 66.It would also help if i knew the formula to solving this.
Found 2 solutions by LtAurora, rfer:
Answer by LtAurora(115) (Show Source): You can put this solution on YOUR website!
Whenever you are given a problem with consecutive integers, you have your first integer, (x), and your next integer (x+2). If you have any more consecutive integers you would have (x+4), (x+6), etc.
This is like saying your first number is 2, the next consecutive even integer would be 4, which you have to add 2 to get to. If you had three consecutive integers in your problem, your next conxecutive integer would be 6, which you would have to add 4 to get to (2+4=6).
So, for this particular problem, you have:

We can combine like terms:

Move the 2 over:

Divide both sides by 2:

This is the first of the consecutive even integers. The other one is 32+2=34.
So, your answers are: 32 and 34.
Sorry, there is no exact formula to solve it, but I hope the method helps.
Answer by rfer(16322) (Show Source): You can put this solution on YOUR website!
x+2+x=66
2x=64
x=32
x+2=34
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