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put this solution on YOUR website!find four consecutive ODD integers
x, x+2, x+4, x+6
;
such that four less than twice the second has the same value as three times the number that is one more than the third.
2(x+2) - 4 = 3((x+4)+1)
2x + 4 - 4 = 3(x+5)
2x = 3x + 15
-15 = 3x - 2x
x = -15
:
The four numbers: -15, -13, -11, -9
:
:
Check solution in the given statement:
"four less than twice the second has the same value as three times the number that is one more than the third."
2(-13) - 4 = 3(-11 + 1)
-26 - 4 = 3(-10)