SOLUTION: Find the three consecutive integers such that the sum of the first and second is 9 more than half of the third
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Question 221309: Find the three consecutive integers such that the sum of the first and second is 9 more than half of the third
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
Find the three consecutive integers such that the sum of the first and second is 9 more than half of the third
Step 1. Let n be the first integer.
Step 2. Let n+1 and n+2 be the next two consecutive integers.
Step 3. Let n+n+1=2n+1 be the sum of the first and second integers.
Step 4. Let since 9 more than half of the third integer.
Step 5. Then since the sum of the first and second is 9 more than half of the third
Step 6. Solving yields the following steps
Multiply 2 to both sides of the equation
Subtract n+2 from both sides of the equation
Divide 3 to both sides of the equation
and
Check in Step 5 2*6+1=8/2+9 or 12+1=4+9 which is a true statement.
Step 7. ANSWER: The three consecutive and even integers are 6, 7 and 8.
I hope the above steps were helpful.
For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.
Good luck in your studies!
Respectfully,
Dr J
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