SOLUTION: The sum of two nubers is 10. The sum of their squares is 52. Find the numbers.
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Question 219692: The sum of two nubers is 10. The sum of their squares is 52. Find the numbers.
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
x+y=10 or x=10-y
x^2+y^2=52
(10-y)^2+y^2=52
100-20y+y^2+y^2=52
2y^2-20y+100-52=0
2y^2-20y+48=0
2(y^2-10y+24)=0
2(x-6)(x-4)=0
(x-6=0
x=6 ans.
6+y=10
y=10-6
y=4 ans.
x-4=0
x=4 ans,
4+y=10
y=10-4
y=6 ans.
Proof:
4^2+6^2=52
16+36=52
52=52
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