SOLUTION: Find two positive numbers so that twice the sum equals their product and one number is 6 times the other number

Question 218132: Find two positive numbers so that twice the sum equals their product and one number is 6 times the other number
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
Let x &y = numbers
.
x=6y
.
2(x+y) = xy,,,,,,,,substitute
,
2{6y+y} ={6y}y
.
14y =6y^2
.
0=6y^2 -14y
.
0 = y(6y-14) =0
.
y=0,,,,,,,,,y=14/6 = 7/3
.
x=0,,,,,,,,,x= 14
.
.
check,,,,(0,0),,,,0=0,,,,,ok,,,but not positive number
.
(14,7/3),,,,,2(14+7/3) = (14)(7/3) = 32.67,,,,,ok
.

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