SOLUTION: the squares of 2 consecutive odd numbers differ by 88, what are the numbers?
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Question 217651: the squares of 2 consecutive odd numbers differ by 88, what are the numbers?
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
Let x,,,,x+2 ,,,,be consecutive odd numbers
.
(x+2)^2 -(x)^2 =88
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x^2 +4x +4 -x^2 =88
.
4x =84
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x=21
.
Numbers are 21,,23
.
.
check
23^2-21^2 = 88,,,,,,ok
.
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