You can
put this solution on YOUR website!The question asks the sum of three consecutive even integers is 30 more than the largest. What will be the integers? The domain for the smallest integers: {14, 18, 20} Can you help me? Is there a 5 step plan I can use?
Step 1. Let n be one even integer.
Step 2. Let n+2 and n+4 be the next two consecutive integers where n+4 be the largest integer.
Step 3. Let n+n+2+n+4= 3n+6 be the sum of the even integer.
Step 4. Then 3n+6=n+4+30 since the sum of three consecutive even integers is 30 more than the largest
Step 5. The following will solve the equation in Step 4.
Add -6-n to both side of the equation to get n-terms only on the left side and numbers only on the right.
Divide by 2 to both sides of the equation
and
and
Check equation in Steps 3 and 4 if true...then 14+16+18=18+30...which is a true statement.
Step 6. ANSWER: The three consecutive and even integers are 14, 16, and 18.
I hope the above steps were helpful.
For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.
And good luck in your studies!
Respectfully,
Dr J
