SOLUTION: three consecutive odd numbers, such that three times the 1st is the sum of the 2nd and 3rd . If you use algebra which I did, you get three even numbers 3x = (x+2)+(x+4) what's

Question 216890: three consecutive odd numbers, such that three times the 1st is the sum of the 2nd and 3rd .
If you use algebra which I did, you get three even numbers 3x = (x+2)+(x+4)
what's the solution then?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
three consecutive odd numbers, such that three times the 1st is the sum of the 2nd and 3rd .
If you use algebra which I did, you get three even numbers 3x = (x+2)+(x+4)
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3x = x+2 + x+4 = 2x+6
x = 6
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3*6 is 8+10
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They have to be even numbers. The sum of any 2 odd numbers is an even number, and the sum of any 2 even numbers is also even.
In other words, there are no odd numbers that fit.
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