SOLUTION: find three consecutive integers such that the sum of one-half of the smallest and one-third of the largest is one less than the other integer

SOLUTION: find three consecutive integers such that the sum of one-half of the smallest and one-third of the largest is one less than the other integer

Algebra.Com

Question 216620: find three consecutive integers such that the sum of one-half of the smallest and one-third of the largest is one less than the other integer
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
Let x,,,,x+1,,,,,x+2,,,,be consecutive integers
.
(x/2) + { (x+2)/3} = (x+1) -1
.
x/2 + x/3 +2/3 = x,,,,,mult by 6
.
3x +2x +4 = 6x
.
4=x,,,,,,,x+1=5,,,,,x+2=6
.
.
checking
4/2 + 6/3 = 5-1
.
2+2 =4,,,,,,ok
.

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