SOLUTION: the sum of twelve and an unknown number is four times the unknown number.

Question 214809: the sum of twelve and an unknown number is four times the unknown number.
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
x is the unknown number
12 + x = 4*x
subtract x from both sides of this equation to get:
12 = 3*x
divide both sides of this equation by 3 to get:
4 = x which is the same as:
x = 4
-----
let x = 4 in your original equation.
12 + 4 = 4*4 becomes:
16 = 16 confirming that x = 4 is a good number.
-----
RELATED QUESTIONS
the sum of an unknown number and 12 is subtracted from 4 times the unknown number, the... (answered by ankor@dixie-net.com)

When 3 times the sum of 4 and an unknown number is subtracted from 10 times the unknown... (answered by RAY100,PRMath)

When Twice The Sum of 5 and an Unknown Number is Subtracted from 8 Times the Unknown... (answered by CubeyThePenguin)

Four times a number is equal to twice the sum of five and that number find the unknown... (answered by ptaylor)

what is the answer?four times an unknown number is subtracted from twenty five is equal... (answered by Stitch)

six plus an unknown number is equal to twelve decreased by the unknown number. what is... (answered by robertb)

Twelve more than the square of the difference of four times a number and eight in... (answered by JoelSchwartz,ewatrrr)

five more than eight times an unknown number is -35. Find the unknown... (answered by oberobic)

an unknown number increased by four times the same number is... (answered by edjones)