You can
put this solution on YOUR website!let n = "1st number"
"The second number is 8 less than the first number" ___ n - 8
"the third is 4 more than the first number" ___ n + 4
"The sum of three numbers is 120" ___ n + n - 8 + n + 4 = 120
3n - 4 = 120 ___ 3n = 124 ___ n = 124/3 = 41 1/3
substituting ___ n - 8 = 33 1/3
substituting ___ n + 4 = 45 1/3
You can
put this solution on YOUR website!
OK
Let x=the first number
then x-8=second number
and x+4=third number
Now we are told that:
x+(x-8)+(x+4)=120 simplify
x+x-8+x+4=120
3x-4=120 add 4 to each side
3x-4+4=120+4 or
3x=124 divide each side by 3
x=41 1/3-----------first number
x-8=(41 1/3)-8=33 1/3------------second number
x+4=(41 1/3)+4=45 1/3 --------------------third number
CK
(41 1/3)+(33 1/3) + (45 1/3)=120
120=120
Hope this helps---ptaylor