Step 1. Let n be an odd integer then n+2 be the next odd consecutive integer
Step 2. n(n+2) is the product of the two odd integers.
Step 3. n+n+2 is the sum of the two odd integers.
Step 4. n(n+2)=15+3(n+n+2) product is 15 more than sum.
Step 5. Solve the equation in Step 4 using the following steps.
| Solved by pluggable solver: EXPLAIN simplification of an expression | |
Your Result: YOUR ANSWERDETAILED EXPLANATIONLook at Moved It becomes Look at Eliminated similar terms It becomes Look at Added fractions or integers together It becomes Look at Remove unneeded parentheses around factor It becomes Look at Moved these terms to the left It becomes Look at Expanded term It becomes Look at Reduce similar several occurrences of It becomes Look at Expanded term It becomes Look at Multiplied numerator integers It becomes Look at Multiplied numerator integers It becomes Look at Added fractions or integers together It becomes Look at Removed extra sign in front of It becomes Look at Eliminated similar terms It becomes Look at Added fractions or integers together It becomes Look at Removed extra sign in front of It becomes Look at Remove unneeded parentheses around factor It becomes Look at Equation It becomes Result: This is an equation! Solutions: n=7,n=-3. Universal Simplifier and SolverDone! |
Step 6. There are two solutions 7 and 9 is one solution set and the other -3 and -1 is another solution set.
I hope the above steps were helpful.
For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.
And good luck in your studies!
Respectfully,
Dr J