SOLUTION: Find two consecutive even integers such that three times the lesser integer, added to the larger integer, is 58.

Question 214097: Find two consecutive even integers such that three times the lesser integer, added to the larger integer, is 58.
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
Find two consecutive even integers such that three times the lesser integer, added to the larger integer, is 58.

Step 1. Let n be an even integer and n+2 be the next consecutive even integer

Step 2. 3n be three times the lesser integer

Step 3. 3n+n+2 be three times the lesser integer added to the larger integer n+2

Step 4. 3n+n+2=58 be three times the less integer added to the larger integer n+2 is 58.

Step 5. The following steps will solve the equation 3n+n+2=58.

Solved by pluggable solver: EXPLAIN simplification of an expression

Your Result:

YOUR ANSWER

This is an equation! Solutions: n=14.
Graphical form: Equation was fully solved.
Text form: 3n+n+2=58 simplifies to 0=0
Cartoon (animation) form:
For tutors: simplify_cartoon( 3n+n+2=58 )
If you have a website, here's a link to this solution.

DETAILED EXPLANATION

Look at .
Eliminated similar terms highlight_red%28+3%2An+%29

replacing them with highlight_green%28+%283%2B1%29%2An+%29

It becomes .

Look at .
Added fractions or integers together
It becomes .

Look at .
Remove unneeded parentheses around factor highlight_red%28+4+%29

It becomes .

Look at .
Moved these terms to the left highlight_green%28+-58+%29

It becomes .

Look at .
Added fractions or integers together
It becomes .

Look at .
Removed extra sign in front of

It becomes .

Look at .
Solved linear equation highlight_red%28+4%2An-56=0+%29

equivalent to 4*n-56 =0
It becomes .
Result:
This is an equation! Solutions: n=14.

Universal Simplifier and Solver

Done!

Then n+2=16 when n=14

Check 3*14+16=58. So it works!!

Step 6. ANSWER: The integers are 14 and 16.

I hope the above steps were helpful.

For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J
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