SOLUTION: how do solve base and height trianlges? the question:the base of a triangle is 9cm greater than the height. the area is 56cm^2.Find the base and height. my answer:b=h+9

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Question 21295: how do solve base and height trianlges?
the question:the base of a triangle is 9cm greater than the height. the area is 56cm^2.Find the base and height.
my answer:b=h+9
A=56cm^2
56=(h+9)h
0=h^2+9h-56
then thats where i get stuck can you help please.
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
You forgot the "1/2" in the area formula.
Area = (1/2)(base)(height)
56 = (1/2)(h+9)(h)
112 = h^2+9h
h^2+9h-112=0
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=529 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 7, -16. Here's your graph:
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