SOLUTION: Three times the greatest of three consecutive even integers exceeds twice the least by 38. what are the integers? Tried 3(x+4) +38=2x and 3(x+4)=2x+38 both resulted in equalitie

Algebra.Com
Question 212854This question is from textbook
: Three times the greatest of three consecutive even integers exceeds twice the least by 38. what are the integers?
Tried 3(x+4) +38=2x and 3(x+4)=2x+38 both resulted in equalities
This question is from textbook

Found 2 solutions by checkley77, scott8148:
Answer by checkley77(12844)   (Show Source): You can put this solution on YOUR website!
3(x+4)=2x+38
3x+12=2x+38
3x-2x=38-12
x=26 ans. for the smallest integer.
Poof:
3(26+4)=2*26+38
3*30=52+38
90=90

Answer by scott8148(6628)   (Show Source): You can put this solution on YOUR website!
your 2nd equation is the correct one, with x equaling the smallest integer
RELATED QUESTIONS

Three times the greatest of three consecutive even integers exceeds twice the least by... (answered by robertb)
Three times the greatest of three consecutive even integers exceeds twice the least by... (answered by CubeyThePenguin)
Three times the greatest of 3 consecutive even integers exceeds twice the least by 38.... (answered by checkley77)
Three times the greatest of three consecutive even integers exceeds twice the least by... (answered by mananth)
Three times the greatest of three consecutive even integers exceeds twice the least by... (answered by neatmath)
Three times the greatest of the three consecutive even integers exceeds twice the least... (answered by ewatrrr)
please help me with solving the equation: Three times the greatest of three consecutive... (answered by solver91311)
Three times the greater of three consecutive even integers exceeds twice the least by 38. (answered by user_dude2008)
Three times the largest of three consecutive even integers exceeds twice the least... (answered by macston,stanbon)