SOLUTION: The sum of two numbers is 25. Twelve less than four times one of the numbers is 16 more than twice the other number. Find both Numbers.

Question 212840: The sum of two numbers is 25. Twelve less than four times one of the numbers is 16 more than twice the other number. Find both Numbers.
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
The sum of two numbers is 25. Twelve less than four times one of the numbers is 16 more than twice the other number. Find both Numbers.

Step 1. Let m be one number.

Step 2. Let n be the other number

Step 3. m+n=25 or n=25-m

Step 4. 4n-12 (Twelve less than four times one of the numbers)

Step 5. 2m+16 (16 more than twice the other number)

Step 6. Set equation Steps 4 and 5 to be equal and find the numbers.

Substitute n=25-m into above equation

Add 4m-16 to both sides of equation to isolate m terms on right side and numbers on left side

Divide by 6 to both sides

Step 7. ANSWER: So m=12 and n=25-12=13

NOTE: Let's verify the above numbers with the problem statement: Twelve less than four times one of the numbers is 16 more than twice the other number. Find both Numbers.

So it works!

I hope the above steps were helpful.

For Step-By-Step free videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

Good luck in your studies!

Respectfully,
Dr J

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