SOLUTION: Find two consecutive odd integers such that 3 times the first is 5 more than twice the second Thank you very much

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Question 212405: Find two consecutive odd integers such that 3 times the first is 5 more than twice the second
Thank you very much
Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
Find two consecutive odd integers such that 3 times the first is 5 more than twice the second



Step 1. Let n be one odd integer.

Step 2. Let n+2 be the next odd integer.

Step 3. Generate an equation for the given problem statement: Find two consecutive odd integers such that 3 times the first IS 5 more than twice the second. 3n is one side of equation and 5+2(n+2) is the opposite side of equation. "is" in the given problem statement implies "equal to" so

3n+=+5%2B2%28n%2B2%29

3n+=+5%2B2n%2B4

Step 4. Solve for n. Subtract 2n from both sides of equation.

3n-2n+=+5%2B2n%2B4-2n

n+=+9

n%2B2+=+11

Check numbers with problem statement.

3%28n%29=3%289%29=27

2%28n%2B2%29=2%2811%29=22 so 27 is 5 more than twice 11. So numbers are odd and satisfies problem statement.

Step 5. ANSWER: Numbers are 9 and 11.


Hope the steps were helpful. Good luck in your studies.
Respectfully,
Dr J

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