SOLUTION: Find two consecutive odd integers such that 3 times the first is 5 more than twice the second
Thank you very much
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Question 212405: Find two consecutive odd integers such that 3 times the first is 5 more than twice the second
Thank you very much
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
Find two consecutive odd integers such that 3 times the first is 5 more than twice the second
Step 1. Let n be one odd integer.
Step 2. Let n+2 be the next odd integer.
Step 3. Generate an equation for the given problem statement: Find two consecutive odd integers such that 3 times the first IS 5 more than twice the second. 3n is one side of equation and 5+2(n+2) is the opposite side of equation. "is" in the given problem statement implies "equal to" so
Step 4. Solve for n. Subtract 2n from both sides of equation.
Check numbers with problem statement.
so 27 is 5 more than twice 11. So numbers are odd and satisfies problem statement.
Step 5. ANSWER: Numbers are 9 and 11.
Hope the steps were helpful. Good luck in your studies.
Respectfully,
Dr J
For Step-By-Step videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra.
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