SOLUTION: If the 3-digit number 27d, in which d is the ones' digit, is evenly divisible by both 3 and 4, what is the value of d?

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Question 21201: If the 3-digit number 27d, in which d is the ones' digit, is evenly divisible by both 3 and 4, what is the value of d?
Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
to be divisible by 3, the digits must add up to a number that is itself divisible by 3.

So 271 --> 2+7+1 = 10, which is not disible by 3, so neither is 271.

note the 2+7 add up to 9, so the value of d must be a 3, 6 or 9 to keep this rule.

Any number divisible by 4 has to be even, so this means of the 3 options, 273, 276 or 279, we are left with just 276.

jon.