SOLUTION: find three consecutive odd integers such that the sum of the first, two times the second, and three times the third is 82

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 Question 211365: find three consecutive odd integers such that the sum of the first, two times the second, and three times the third is 82Found 2 solutions by checkley77, RAY100:Answer by checkley77(12569)   (Show Source): You can put this solution on YOUR website!Let x, x+2 & x+4 be the three integers. x+2(x+2)+3(x+4)=82 x+2x+4+3x+12=82 6x=82-4-12 6x=66 x=66/6 x=11 the smallest integer. 11=2=13 for the next integer. 11=4=15 for the largest integer. Proof: 11+2*13+3*15=82 11+26+45=82 82=82 Answer by RAY100(1637)   (Show Source): You can put this solution on YOUR website!Let x=1st integer, x+2 = 2nd integer, and x+4 = 3rd integer . 1(x) +2(x+2) +3(x+4) = 82 . x+2x+4+3x+12 =82 . 6x + 16 =82 . 6x=66 . x=11 . Integers are 11,13,15, . . check,,11 +2*13 +3*15 = 82,,,,,ok .