Question 204160: how to solve this question using algebraic formula: There are 26 heads and 74 legs, how many chicken and sheep in the farm? Found 3 solutions by Alan3354, ichudov, MathTherapy:Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website! how to solve this question using algebraic formula: There are 26 heads and 74 legs, how many chicken and sheep in the farm?
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c = # of chickens
s = # of sheep
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Chickens have 2 legs, sheep have 4. They all have 1 head each.
Legs = 2c + 4s = 74
c + 2s = 37 (divided by 2)
c + s = 26
-------------- Subtract
0c+ s = 11
There are 11 sheep.
26-11 = 15 chickens. Answer by ichudov(507) (Show Source): You can put this solution on YOUR website!
Solve: We'll use substitution. After moving 1*sheep to the right, we get: , or . Substitute that
into another equation: and simplify: So, we know that sheep=11. Since , chicken=15.
Answer: .
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
Let the amount of chickens be c, and the amount of sheep be s
Since there are 26 heads, then we’ll have: c + s = 26
Since there are 74 legs and since chickens have 2 legs, while sheep have 4, we’ll then have: 2c + 4s = 74
We now have he following 2 simultaneous equations:
c + s = 26 (multiply by – 2) -----> - 2c - 2s = - 52
2c + 4s = 74 (multiply by 1) -----> 2c + 4s = 74
Add eq (i) & eq (ii) -----------------> 2s = 22
s = 11
Substituting 11 for s in eq (i), we get: c + 11 = 26
c = 15
Therefore, there are chickens, and sheep on the farm.