SOLUTION: Find 3 consecutive even numbers where the product of the smaller two numbers is 64 less than the square of the largest number

SOLUTION: Find 3 consecutive even numbers where the product of the smaller two numbers is 64 less than the square of the largest number

Algebra.Com

Question 202095: Find 3 consecutive even numbers where the product of the smaller two numbers is 64 less than the square of the largest number
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
x, x+2, x+4 are the 3 even numbers.
x(x+2)+64=(x+4)^2
x^2+2x+64=x^2+8x+16
2x-8x=-64+16
-6x=-48
x=-48/-6
x=8 ans. for the smaller number
8+2=10 for the middle number
8+4=12 for the larger number
Proof:
8(10)+64=12^2
80+64=144
144=144
RELATED QUESTIONS
Find 3 consecutive even numbers where the product of the smaller two numbers is 64 less... (answered by ankor@dixie-net.com)

Find 3 consecutive even numbers where the product of the smaller two numbers is 40 less... (answered by Mathematicians,oberobic)

Find 3 consecutive even numbers where the product of the smaller two numbers is 52 less... (answered by mananth)

Find 3 consecutive even numbers where the product of the smaller two numbers is 40 less... (answered by mananth)

3 consecutive even numbers where the product of the smaller two numbers is 52 less than... (answered by checkley77,MathTherapy)

Find three consecutive even numbers where the product of the smaller two numbers is 64... (answered by valentity)

find 3 consecutive even numbers where the product of the two smaller numbers is 52 less... (answered by LinnW)

Find three consecutive even numbers where the product of the smaller two is 40 less than... (answered by ankor@dixie-net.com)

Find 3 consecutive even numbers whenthe product of the smaller two numbers is 40 less... (answered by JBarnum)