SOLUTION: Find three consecutive even numbers where the product of the smaller two is 40 less than the square of the largest number.

Question 200138: Find three consecutive even numbers where the product of the smaller two is 40 less than the square of the largest number.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Find three consecutive even numbers where the product of the smaller two is 40
less than the square of the largest number.
:
Three consecutive even numbers: x, (x+2), (x+4)
:
"the product of the smaller two is 40 less than the square of the largest number."
x(x+2) = (x+4)^2 - 40
:
x^2 + 2x = x^2 + 8x + 16 - 40
:
Combine the x's on the left, number on the right
x^2 - x^2 + 2x - 8x = -24
:
-6x = -24
x =
x = +4, 6, 8 are the numbers
:
:
Check solution in the statement:
"the product of the smaller two is 40 less than the square of the largest number."
4 * 6 = 8^2 - 40
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