SOLUTION: Find three consecutive integers such that 3 times the first integer plus the second integer minus 2 times the third integer is 9.

SOLUTION: Find three consecutive integers such that 3 times the first integer plus the second integer minus 2 times the third integer is 9.

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Question 194685: Find three consecutive integers such that 3 times the first integer plus the second integer minus 2 times the third integer is 9.
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
Let x, x+1 & x+2 be the 3 integers.
3x+(x+1)-2(x+2)=9
3x+x+1-2x-4=9
2x-3=9
2x=9+3
2x=12
x=12/2
x=6 ans. for the first integer.
6+1=7 ans. for the second integer.
6+2=8 ans. for the largest integer.
Proof:
3*6+7-2*8=9
18+7-16=9
25-16=9
9=9

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