SOLUTION: One coin is 2 years older than another. In 3 years, the product of their ages will be 35. Find the present ages of the coins. _______ and _______ I am stumped. Thank you! Jes

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Question 188263: One coin is 2 years older than another. In 3 years, the product of their ages will be 35. Find the present ages of the coins. _______ and _______
I am stumped. Thank you! Jessica
Answer by Alan3354(21605) About Me  (Show Source):
You can put this solution on YOUR website!
One coin is 2 years older than another. In 3 years, the product of their ages will be 35. Find the present ages of the coins. _______ and _______
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age of 1st coin = y (number of years)
age of 2nd coin = y+2
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In 3 years:
(y+3)*(y+5) = 35
y%5E2+%2B+8y+%2B+15+=+35
y%5E2+%2B+8y+-+20+=+0
(y + 10)*(y - 2) = 0
y = 2 years (ignore the -10)
2nd coin is 4 years old