SOLUTION: The sum of two numbers is equal to twice their difference. If one number is 4 more than the other, find the numbers. I did A=first # a=2nd # Then A+a=2(A-a) A=2a+4 but i

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Numbers -> SOLUTION: The sum of two numbers is equal to twice their difference. If one number is 4 more than the other, find the numbers. I did A=first # a=2nd # Then A+a=2(A-a) A=2a+4 but i      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

   

Question 183408: The sum of two numbers is equal to twice their difference. If one number is 4 more than the other, find the numbers.
I did A=first # a=2nd #
Then A+a=2(A-a) A=2a+4
but it does not come out right.
Please help.
Anne
Answer by jim_thompson5910(21685) About Me  (Show Source):
You can put this solution on YOUR website!
Let x=first number, y=second number

"The sum of two numbers is equal to twice their difference" translates to x%2By=2%28x-y%29 Note: I'm implying that "x" is bigger than "y"


Also, " If one number is 4 more than the other" means that x=y%2B4


x%2By=2%28x-y%29 Start with the first equation


y%2B4%2By=2%28y%2B4-y%29 Plug in x=y%2B4


2y%2B4=2%284%29 Combine like terms.


2y%2B4=8 Multiply


2y=4 Subtract 4 from both sides


y=2 Divide both sides by 2 to isolate y



x=y%2B4 Go back to the second equation


x=2%2B4 Plug in y=2


x=6 Add


==================================

Answer:


So the solutions are x=6 and y=2 which means that the two numbers are 6 and 2