SOLUTION: Find three consecutive even numbers whose sum is 54 Ok..first write a "let statement": x= 1st cons. even number x+2= 2nd cons. even number x+4= 3rd cons. even number Now re-wr

Question 18245: Find three consecutive even numbers whose sum is 54
Ok..first write a "let statement":
x= 1st cons. even number
x+2= 2nd cons. even number
x+4= 3rd cons. even number
Now re-write the problem:
x+(x+2)+(x+4)=54
Now combine like terms:
3x+6=54
Now solve:
Subtract 6 on both sides:
3x=48
Divide by 3 on both sides:
x=16
x+2=18
x+4=20
Hope I helped! ^^
Found 2 solutions by Kuroinu, lilmathgrl92:
Answer by Kuroinu(8) (Show Source):
You can put this solution on YOUR website!
Start off by assigning the lowest number a variable, such as "x" and then assign values to the other two numbers in relation to that variable. Because these are consecutive even numbers, then your values would be x, x+2, and x+4. You would then put them into an equation. x+(x+2)+(x+4)=54 Simplify this to 3x+6=54, subtract 6 from both sides to get 3x=48, and then divide both sides of the equation by 3 to get x=16. 16 would be your lowest integer, so the next two would be 18 and 20. You can check your answer to a problem like this by adding them and making sure they equal the given sum. In this case, 16, 18, and 20 do add up to 54, so that would be the correct answer. I hope this helps.

Answer by lilmathgrl92(3) (Show Source):
You can put this solution on YOUR website!