SOLUTION: Find the two-digit number whose tens digit is 4 less than its units digit if the orignal number is 2 more than 3 times the sum of the digits.

Question 180016: Find the two-digit number whose tens digit is 4 less than its units digit if the orignal number is 2 more than 3 times the sum of the digits.
Found 2 solutions by Mathtut, ankor@dixie-net.com:
Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!
Find the two-digit number whose tens digit is 4 less than its units digit if the orignal number is 2 more than 3 times the sum of the digits.
:
let the two digit number be ab--->remembering that ab = 10a+b
:
a=b-4............eq 1
10a+b=3(a+b)+2......eq 2
:
take a's value in eq 1 and plug it into eq 2
10(b-4)+b=3(b-4)+3b+2
:
10b-40+b=3b-12+3b+2
:
5b=30
:
units digit
:
tens unit
:
number is 26
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Find the two-digit number whose tens digit is 4 less than its units digit
if the original number is 2 more than 3 times the sum of the digits.
:
Let x = 10s digit
Let y - units digit
:
10x + y = the number
:
the two-digit number whose tens digit is 4 less than its units digit"
x = y - 4
:
"the original number is 2 more than 3 times the sum of the digits."
10x + y = 3(x+y) + 2
10x + y = 3x + 3y + 2
10x - 3x = 3y - y + 2
7x = 2y + 2
Replace x with (y-4), find y
7(y-4) = 2y + 2
7y - 28 = 2y + 2
7y - 2y = 2 + 28
5y = 30
y = 6
then
x = 6 - 4
x = 2
:
The original number: 26
:
:
Check solution in the statement:
"the original number is 2 more than 3 times the sum of the digits."
26 = 3(2+6) + 2
26 = 3(8) + 2; confirms our solution
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