Question 179732: I need to find four consecutive odd integers if three times the second number is 15 greater than twice the fourth integer Answer by solver91311(12126) (Show Source):
Let the first odd iteger be x. Then the second odd integer is x + 2, the third is x + 4, and the fourth is x + 6. That's because you always add 2 to get to the next consecutive odd integer.
Three times the second number is then which is equal to two times the fourth number plus 15 or
So:
Solve this for x to get the first of the consecutive odd integers, and then add two, add two, and add two to get the other three.
