SOLUTION: twice the smallest of three consecutive odd integers is 7 more than the largest.
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Word Problems: Numbers, consecutive odd/even, digits
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Question 176657
:
twice the smallest of three consecutive odd integers is 7 more than the largest.
Answer by
Mathtut(3670)
(
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):
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let the integers be a,a+2,a+4
:
2a=a+4+7
:
a=11
:
integers
(