SOLUTION: The sum of 3 numbers is 137. The 2nd number is 4 more than twice the first number and the 3rd number is 5 less than 3 times the first. What are the numbers? And what is the form

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Question 169605: The sum of 3 numbers is 137. The 2nd number is 4 more than twice the first number and the 3rd number is 5 less than 3 times the first. What are the numbers? And what is the formula for finding the numbers please?
Found 2 solutions by Mathtut, checkley77:
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
lets call the 3 numbers a,b,and c
:
a+b+c=137.....eq 1
b=2a+4........eq 2
c=3a-5........eq 3
take b value from eq 2 and c value from eq 3 and plug them into eq 1
:
a+(2a+4)+(3a-5)=137
:
6a-1=137
:
6a=138
:
highlight%28a=23%29
highlight%28b=2%2823%29%2B4=50%29
highlight%28c=3%2823%29-5=64%29

Answer by checkley77(12569) About Me  (Show Source):
You can put this solution on YOUR website!
X+Y+Z=137
Y=2X+4
Z=3X-5
X+(2X+4)+(3X-5)=137
6X-1=137
6X=137+1
6X=138
X=138/6
X=23 FOR THE FIRST NUMBER.
Y=2*23+4=46+4=50 FOR THE SECOND NUMBER.
Z=3*23-5=69-5=64 FOR THE LAST NUMBER.
pROOF:
23+50+64=137
137=137