# SOLUTION: Forty eight more than the second of three consecutive odd integers is the sum of the first and 2/3 of the third. Find the three integers.

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 Click here to see ALL problems on Numbers Word Problems Question 169112: Forty eight more than the second of three consecutive odd integers is the sum of the first and 2/3 of the third. Find the three integers.Answer by ankor@dixie-net.com(15639)   (Show Source): You can put this solution on YOUR website!Forty eight more than the second of three consecutive odd integers is the sum of the first and 2/3 of the third. Find the three integers. : The three integers: x, (x+2), (x+4) : (x+2) + 48 = x + (x+4) : Multiply equation by 3 to get rid of the fraction 3(x+2) + 3(48) = 3x + 2(x+4) : 3x + 6 + 144 = 3x + 2x + 8 : 150 - 8 = 3x - 3x + 2x : 142 = 2x : x = 71, the 1st odd integer : : Check solution in the original equation 73 + 48 = 71 + 75 121 = 71 + 50