You can
put this solution on YOUR website!ok lets call our 3 consecutive odd integers a+1, a+3,and a+5
so (a+1)+(a+5)=5(a+3)-57 solve for a..... 3a=48 so a=16 so first integer is a+1
which is 17 a+3 is 19 and a+5 which is what we are after is 21
answer:21