SOLUTION: Find three consecutive even integers such that the sum of three times the first integer, one-third the second integer, and eight times the third integer is -58. Thankyou

Question 162820: Find three consecutive even integers such that the sum of three times the first integer, one-third the second integer, and eight times the third integer is -58.
Thankyou
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Find three consecutive even integers
x, (x+2), (x+4)
:
such that the sum of three times the first integer, one-third the second integer, and eight times the third integer is -58
3x + (x+2) + 8(x+4) = -58
:
3x + x + + 8x + 32 = -58
:
11x + 32 = -58
:
11x = -58 - 32
:
11x = -90
Multiply equation by 3
34x = -272
x =
x = -8
:
The three numbers: -8, -6, -4
:
You can check solution in the original equation
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