SOLUTION: Find four consecutive odd integers have a sum of 120. What are the integers?
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Question 162575: Find four consecutive odd integers have a sum of 120. What are the integers?
Found 2 solutions by checkley77, stanbon:
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
let x, x+2, x+4, x+6 be the 4 integers.
x+x+2+x+4+x+6=120
4x+12=120
4x=120-12
4x=108
x=108/4
x=27 for the first integer.
27+2=29 for the next one.
27+4=31 for the next.
27+6=33 for the largest.
Proof:
27+29+31+33=120
120=120
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find four consecutive odd integers have a sum of 120. What are the integers?
----------
1st: 2x+1
2nd: 2x+3
3rd: 2x+5
4th: 2x+7
--------------
EQUATION:
8x + 16 = 120
8x = 104
x = 13
----------
1st: 2x+1 = 27
2nd: 29
3rd: 31
4th: 33
============
Cheers,
Stan H.
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