SOLUTION: Find three consectutive integers such that 4 times the largest exceeds three times the second by 10.

Question 160032: Find three consectutive integers such that 4 times the largest exceeds three times the second by 10.
Answer by KnightOwlTutor(293) (Show Source): You can put this solution on YOUR website!
#1=X
#2=x+1 Send largest
#3=x+2 Largest
4(X+2)=10+3(x+1)
Use the distributive property
4x+8=10+3x+3
Simplify
4x+8=13+3x
Subtract 3x from both sides
x+8=13
Subtract 8 from both sides
X=5
X+1=6
X+2=7
Let's confirm that this is the correct answer by plugging in the respective values into the equation
4(X+2)=10+3(x+1)
4(7)=10+18
28=28
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