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put this solution on YOUR website!3 consecutive integers whose sum is 63
Let the first number be x; then the next consecutive number is x+1, then x+2
so our three consecutive numbers would be;
x, x+1, x+2
so we have for our equation;
x+x+1+x+2=63
Add like terms;
3x+3=63
subtract 3 from both sides;
3x+3-3=63-3
3x=60
Divide 3 from both sides;
=
x=20
So our first number will be 20; cxan you figure out the next 2 numbers?
I hope you understand
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