SOLUTION: if the first and third of three consecutive odd integers are added, the result is 63 less than five times the second integer. Find the third integer.

Question 151185: if the first and third of three consecutive odd integers are added, the result is 63 less than five times the second integer. Find the third integer.
Answer by mangopeeler07(462) (Show Source): You can put this solution on YOUR website!
x=first consecutive odd
x+2=second consecutive odd
x+4=third consecutive odd

first + third= 5(second)-63

Plug in the variables
x+(x+4)=5(x+2)-63

Distribute
x+x+4=5x+10-63

Combine like terms on both sides
2x+4=5x-53

Add 53 to both sides
2x+57=5x

Subtract 2x from both sides
57=3x

Divide both sides by 3
19=x

first consecutive odd=(19)
second consecutive odd=(19)+2
third consecutive odd=(19)+4
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Answer:
first consecutive odd=19
second consecutive odd=21
**third consecutive odd=23**
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