SOLUTION: find three consecutive integers such that 3 times the least is 4 more than twice the greatest

Question 149822: find three consecutive integers such that 3 times the least is 4 more than twice the greatest
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
find three consecutive integers such that 3 times the least is 4 more than twice the greatest
:
"three consecutive integers:
x, (x+1), (x+2)
;
Write an equation for the statement:
"3 times the least is 4 more than twice the greatest"
3x = 4 + 2(x+2)
;
3x = 2x + 4 + 4
:
3x = 2x + 8
:
3x - 2x = 8
:
x = 8, 9, 10 are the 3 integers
:
:
Check solution in the statement:
" 3 times the least is 4 more than twice the greatest"
3(8) = 4 + 2(10); confirms our solution

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