|
Question 149103: I know that I need to have an equation but I don't understand how to make one or what to do next. Please help with steps.
The length of a rectangle is 14 more than the width. The perimeter of the rectangle is 264 meters. What are the dimensions of the rectangle?
Found 3 solutions by solver91311, jojo14344, josmiceli:
Answer by solver91311(12126)   (Show Source):
You can put this solution on YOUR website!The perimeter of a rectangle is given by  where  is the length and  is the width. You are given that the length is 14 more than the width, so you can say  , and you are given that  . So take the equation for the perimeter:
and substitute:
Now all you have to do is solve that equation for W to get the width, and add 14 to that answer to get the length.
Answer by jojo14344(1512)  (Show Source):
You can put this solution on YOUR website!We have to start with formula of finding the Perimeter of Rectangle:
 -----------> eqn 1
.
Next, label the given:
W= unknown
L= W+14, right? (14 more)
P= 264 meters
Substituting in eqn 1,
264= 2(W+14+W)
264= 2(2W+14)=4W+28
For L = 59+14
In doubt? Go back eqn 1,
Thank you,
Jojo
Answer by josmiceli(6786)  (Show Source):
You can put this solution on YOUR website!The opposite sides of a rectangle are equal
They could be 12,12,5 , and 5
or 33,33,8, and 8
or a, a, b, and b
The problem says the perimeter is  meters, so
 meters
If  is the length and  is the width,
 meters
Plug this expression for into the 1st equation
The length is 73 meters and the width is 59 meters
check answer:
and
OK
|
|
|
| |
