You can
put this solution on YOUR website!let t="ten's digit" and u="unit's digit"
"In a two-digit number, the ten's digit is 3 more than the one's digit" __ t=u+3
"If the digits are reversed, the difference between the two numbers is 27" __ (10t+u)-(10u+t)=27
9t-9u=27 __ dividing by 9 __ t-u=3 __ adding u __ t=u+3
since the two equations are basically the same, there is no unique solution
__ any two digits, where one is 3 more than the other, will work
